SQL HELP
#3

Код:
SELECT `ID`, `Password`,  FROM users WHERE Username = '%e'
There is an extra comma after the `Password`.
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Messages In This Thread
SQL HELP - by Pearson - 02.12.2016, 14:19
Re: SQL HELP - by Dayrion - 02.12.2016, 14:25
Re: SQL HELP - by oMa37 - 02.12.2016, 14:33
Re: SQL HELP - by Pearson - 02.12.2016, 14:40

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