[jlalt]

try replacing

PHP код:

        mysql_format(ServerMySQL,query1,sizeof(query1),"UPDATE `Users` SET  Name ='%s',pIP='%s',pCash = %d,pAdmin=%d, pXPos = %f, pYPos = %f, pZPos = %f, pAPos = %f,Interior=%d WHERE Name = '%s'",GetName(playerid),playerip[playerid],cash,PlayerInfo[playerid][pAdmin], pos[0], pos[1], pos[2], pos[3],PlayerInfo[playerid][Interior],GetName(playerid)); 


with:

Код:

        mysql_format(ServerMySQL,query1,sizeof(query1),"UPDATE `Users` SET  `Name` = '%s', `pIP` = '%s', `pCash` = '%d', `pAdmin` = '%d', `pXPos` = '%f', `pYPos` = '%f', `pZPos` = '%f', `pAPos` = '%f', `Interior` = '%d' WHERE `Name` = '%s'",GetName(playerid),playerip[playerid],cash,PlayerInfo[playerid][pAdmin], pos[0], pos[1], pos[2], pos[3],PlayerInfo[playerid][Interior],GetName(playerid));