Choosing random variable
#3

Quote:
Originally Posted by SickAttack
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pawn Код:
new a[5];

a[0]=1;
a[1]=4;
a[2]=0;
a[3]=7;
a[4]=0;

----------------------------------

new b[5], count;
for(new i = 0; i < 5; i ++)
{
    if(a[i] != 0)
    {
        b[count] = a[i];
        count ++;
    }
}

b[random(count)]; // select a random number
I forgot to mention, variables arrays can't change. For example, according to your code if a[0]=0, a[1]=0, a[2]=1 so b[1]=a[2] when I want it to be b[2]=a[2]

and it would be better if other variables woudnt be used to save a[] values
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Messages In This Thread
Choosing random variable - by Aa12 - 24.03.2016, 20:47
Re: Choosing random variable - by SickAttack - 24.03.2016, 21:05
Re: Choosing random variable - by Aa12 - 24.03.2016, 21:27
Re: Choosing random variable - by SickAttack - 24.03.2016, 21:31
Re: Choosing random variable - by Aa12 - 24.03.2016, 22:07

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