[TwinkiDaBoss]

Quote:

Originally Posted by zPain Print the value right after you declare the variable. PHP код: new furnitureid = CreateDynamicObject(fid, HouseInfo[x][ExitX],HouseInfo[x][ExitY],HouseInfo[x][ExitZ], 0,0,0, HouseInfo[x][VirtualWorld],HouseInfo[x][Interior]);  printf("furnitureid = %d", furnitureid);

Yeah sorry couldnt respond till now, well I did and the output for /buyfurniture 2880 is

PHP код:

[05:16:34] furnitureid: 4996