Index problem
#4

Print the value right after you declare the variable.

PHP код:
new furnitureid CreateDynamicObject(fidHouseInfo[x][ExitX],HouseInfo[x][ExitY],HouseInfo[x][ExitZ], 0,0,0HouseInfo[x][VirtualWorld],HouseInfo[x][Interior]); 
printf("furnitureid = %d"furnitureid); 
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Messages In This Thread
Index problem - by TwinkiDaBoss - 18.12.2015, 01:03
Re: Index problem - by zPain - 18.12.2015, 01:42
Re: Index problem - by TwinkiDaBoss - 18.12.2015, 01:46
Re: Index problem - by zPain - 18.12.2015, 02:21
Re: Index problem - by TwinkiDaBoss - 18.12.2015, 03:17
Re: Index problem - by zPain - 18.12.2015, 04:17
Re: Index problem - by vassilis - 18.12.2015, 07:46
Re: Index problem - by TwinkiDaBoss - 18.12.2015, 08:00

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