mysql issue
#2

Likely has nothing to do with that line. It means you are doing something stupid like:
pawn Код:
if(1 == 1)
Although it may not immediately be visible to the naked eye and may manifest itself like:
pawn Код:
#define SOMETHING 1

if(SOMETHING == 1)
Which is always "non-zero" and therefore always "true".

For the latter case, resort to the preprocessor directive, #if.
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mysql issue - by Hybris - 01.10.2015, 17:36
Re: mysql issue - by Vince - 01.10.2015, 17:40

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