[Freezo]

Quote:

Originally Posted by Dutheil Not really, if you put the character '@' before the name, you can't call only the function name. Example which works : PHP код: #include <a_samp> main() {     @test(); } forward @test(); @test() {     print("test"); }  Example doesn't work : PHP код: #include <a_samp> main() {     test(); } forward test(); @test() {     print("test"); }  Код: error 004: function "test" is not implemented warning 235: public function lacks forward declaration (symbol "@test")

i dunno what are you trying to say. But yes, i know when you declare it as @test, you will call it as test() and not @test().

@ is like doing public or nothing.

@test() = public test() or test() =

It was just yesterday that i join samp pawn, i was in amxmodx, they don't do forward for such a thing like that.