[Dutheil]

Quote:

Originally Posted by Freezo True, the character '@' declare a public function| @test() -> public test()

Not really, if you put the character '@' before the name, you can't call only the function name.
Example which works :

PHP код:

#include <a_samp>
main()
{
    @test();
}
forward @test();
@test()
{
    print("test");
} 


Example doesn't work :

PHP код:

#include <a_samp>
main()
{
    test();
}
forward test();
@test()
{
    print("test");
} 


Код:

error 004: function "test" is not implemented
warning 235: public function lacks forward declaration (symbol "@test")