03.09.2015, 12:51
Today I learned that when you declare a function with a name starting with an at sign '@' character, it is automatically detected as a public function.
If you do this:
You will take a "warning 235: public function lacks forward declaration (symbol "@test"), because it is not forward, this means that it is a public function.
If you do this:
PHP код:
@test()
{
}