Quote:
Originally Posted by TN0
PHP код:
CREATE TABLE IF NOT EXIST `admins` (`UID` INT(11) NOT NULL AUTO_INCREMENT, `Lvl` INT(2) NOT NULL, `Nick` VARCHAR(25) NOT NULL, `Report` INT(11) DEFAULT '0' NOT NULL, `Kick` INT(11) DEFAULT '0' NOT NULL, `Jail` INT(11) DEFAULT '0' NOT NULL, `Mute` INT(11) DEFAULT '0' NOT NULL, `Time` VARCHAR(17) NOT NULL, `Vigovor` INT(2) DEFAULT '0' NOT NULL, `Reason1` VARCHAR(64) DEFAULT 'N/A' NOT NULL, `Reason2` VARCHAR(64) DEFAULT 'N/A' NOT NULL, `Reason3` VARCHAR(64) DEFAULT 'N/A' NOT NULL, `Skype` VARCHAR(129) NOT NULL, PRIMARY KEY(`UID`)) AUTO_INCREMENT = 1;
Вроде так. Проверяй. |
PHP код:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'EXIST `admins` (`UID` INT(11) NOT NULL AUTO_INCREMENT, `Lvl` INT(2) NOT NULL, `N' at line 1
