DB[playerid][Job]=strval("Unemployed");
#1

PHP код:
DB[playerid][Job]=strval("Unemployed"); 
this shit doesn't get anything, I mean the DB[playerid][Job] stays blank, I tried to make this function to check it:
PHP код:
new String[256];
format(String,sizeof(String),"Job: %s",DB[playerid][Job]);
SendClientMessage(playerid,-1,String); 
and it's just sending "Job: " which means the variable = nothing.

what should i do?

pls ignore my shitty english i wrote it in a minute and I was too lazy to take a look on the thread before posting it.
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Messages In This Thread
DB[playerid][Job]=strval("Unemployed"); - by Lirbo - 22.07.2015, 17:01
AW: DB[playerid][Job]=strval("Unemployed"); - by BigBrainAFK - 22.07.2015, 17:08
Re: AW: DB[playerid][Job]=strval("Unemployed"); - by Lirbo - 22.07.2015, 17:16
AW: DB[playerid][Job]=strval("Unemployed"); - by Nero_3D - 22.07.2015, 17:29
Re: AW: DB[playerid][Job]=strval("Unemployed"); - by Lirbo - 22.07.2015, 19:36
Re: DB[playerid][Job]=strval("Unemployed"); - by kristo - 22.07.2015, 19:40
Re: DB[playerid][Job]=strval("Unemployed"); - by Lirbo - 22.07.2015, 20:46
Re: DB[playerid][Job]=strval("Unemployed"); - by OwlIT - 22.07.2015, 21:26
Re: DB[playerid][Job]=strval("Unemployed"); - by Lirbo - 22.07.2015, 21:34
Re: DB[playerid][Job]=strval("Unemployed"); - by xVIP3Rx - 22.07.2015, 21:42

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