ssacnf warning: Format specifier does not match parameter count.

Terrorizt
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29.06.2015, 14:16

Код:

if(sscanf(params, "us[256]", target))

u, s[256] = 2 specifiers.
target = 1 parameter.
you forgot 1 parameter

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Re : ssacnf warning: Format specifier does not match parameter count. - by Terrorizt - 29.06.2015, 14:16

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