17.06.2015, 14:53
PHP код:
new money[129];
format(money,sizeof(money), "SELECT price FROM houses WHERE id='%i'", PlayerInfo[playerid][pHouseID]);
new result = mysql_query(1, money, true); //here
Tag Mismatch
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Messages In This Thread
Tag Mismatch - by nezo2001 - 17.06.2015, 14:53
Re: Tag Mismatch - by Darrenr - 17.06.2015, 15:02
Re: Tag Mismatch - by Konstantinos - 17.06.2015, 15:10
Re: Tag Mismatch - by nezo2001 - 17.06.2015, 15:28
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