15.06.2015, 05:26
PHP код:
forward HungerThirstCheck(playerid);
public HungerThirstCheck(playerid)
{
foreach (new i : Player)
{
if (PlayerData[i][pHunger] >= 50)
{
GameTextForPlayer(i, "You are hungry, get something to eat.", 1, 6);
}
if (PlayerData[i][pHunger] >= 25)
{
GameTextForPlayer(i, "You are starving, get something to eat before you die.", 8, 8);
}
if (PlayerData[i][pThirst] >= 50)
{
GameTextForPlayer(i, "You are thirsty, get something to drink.", 8, 8);
}
if (PlayerData[i][pHunger] >= 25)
{
GameTextForPlayer(i, "You are becoming unstable, get something to drink before you dehydrate.", 8, 8);
}
}
}
return 1;
}