[Konstantinos]

Let's view the things again. You got:

pawn Код:

[WARNING] CMySQLHandle::Create - connection already exists

which happens if you call mysql_connect more than once in the same script.

The code seems pretty much fine (don't forget to use "return" if there is no response) so debugging:

pawn Код:

printf("hpass: \"%s\" & pInfo[playerid][Password]: \"%s\"", hpass, pInfo[playerid][Password]);
if(!strcmp(hpass, pInfo[playerid][Password]))

What does it print?