sscanf warning: Format specifier does not match parameter count.

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sscanf warning: Format specifier does not match parameter count.

xVIP3Rx
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#2

20.01.2015, 14:58

This happens when you do this:

pawn Код:

new id, secid;
if(sscanf(params, "dd", id))//missing one parameter..

It should happen when you do a command, try to investigate which command is it and fix it.

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Messages In This Thread

sscanf warning: Format specifier does not match parameter count. - by DavidSparks - 20.01.2015, 14:43

Re: sscanf warning: Format specifier does not match parameter count. - by xVIP3Rx - 20.01.2015, 14:58

Re: sscanf warning: Format specifier does not match parameter count. - by DavidSparks - 20.01.2015, 15:00

Re: sscanf warning: Format specifier does not match parameter count. - by HY - 20.01.2015, 15:01

Respuesta: Re: sscanf warning: Format specifier does not match parameter count. - by kirk - 20.01.2015, 15:03

Re: sscanf warning: Format specifier does not match parameter count. - by xVIP3Rx - 20.01.2015, 15:04

Re: sscanf warning: Format specifier does not match parameter count. - by LivingLikeYouDo - 20.01.2015, 15:09

Re: sscanf warning: Format specifier does not match parameter count. - by DavidSparks - 20.01.2015, 15:20

Re: sscanf warning: Format specifier does not match parameter count. - by xVIP3Rx - 20.01.2015, 15:24

Re: sscanf warning: Format specifier does not match parameter count. - by DavidSparks - 20.01.2015, 15:30

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