Duda Mysql

Duda Mysql

[J]ulian
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27.08.2014, 01:34

PHP код:



$query = mysql_query("SELECT * FROM `usuarios` WHERE `Nombre` = '" . mysql_real_escape_string($NICK) . "';"); 

$row = mysql_fetch_assoc($query);

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Duda Mysql - by Unrea1 - 26.08.2014, 22:53

Re: Duda Mysql - by Unrea1 - 26.08.2014, 23:57

Re: Duda Mysql - by Unrea1 - 27.08.2014, 01:29

Respuesta: Duda Mysql - by [J]ulian - 27.08.2014, 01:34

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