[Wizzy951]

Quote:

Originally Posted by HardRock PHP код: format(query, sizeof(query), "UPDATE players SET Age = %d WHERE Name = '%s'", inputtext, Name(playerid));  //Edit: And remove.... PHP код: mysql_real_escape_string(inputtext, EscAge);

I will try it.
EDIT: Oops, I copy-pasted another function, so instead of checking if the entered value is suitable (between 18 and 80) I'm checking the lenght of the entered value and I have to enter 18 characters long value to make it work.