#2

PHP код:
format(querysizeof(query), "UPDATE players SET Age = %d WHERE Name = '%s'"inputtextName(playerid)); 
//Edit: And remove....

PHP код:
mysql_real_escape_string(inputtextEscAge); 
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Messages In This Thread
Age - by Wizzy951 - 17.11.2013, 20:14
Re: Age - by HardRock - 17.11.2013, 20:19
Re: Age - by Ardendshy - 17.11.2013, 20:32
Re: Age - by Wizzy951 - 17.11.2013, 20:37

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