mysql_format
#1

Hi guys !

i have problems with mysql_format and mysql_function_query

here is the code:
pawn Код:
// ERROR LINE -> mysql_format(1,string,"SELECT * FROM `Igraci` WHERE pProfil = '%s'",plname);
    mysql_function_query(1,string,false,"CheckAccountExists","s",plname);
and I get this error:
Код:
error 035: argument type mismatch (argument 3)
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Messages In This Thread
mysql_format - by NeroX98 - 03.07.2013, 12:52
Re: mysql_format - by Vince - 03.07.2013, 13:17
Re: mysql_format - by Luis- - 03.07.2013, 15:11

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