Mysql Escape
#3

Thank you, This is what i have i dont know why its not working. do you see anything wrong ?

PHP код:
    format(Querysizeof(Query), "SELECT * FROM `gta` WHERE 'username' = '%s'"DB_Escape(username));
    
Result db_query(DatabaseQuery
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Messages In This Thread
Mysql Escape - by Dotayuri - 14.02.2013, 07:30
Re: Mysql Escape - by 3ventic - 14.02.2013, 07:53
Re: Mysql Escape - by Dotayuri - 14.02.2013, 08:03
Re: Mysql Escape - by iggy1 - 14.02.2013, 08:44
Re: Mysql Escape - by Dotayuri - 14.02.2013, 10:43

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