SQL issue.
#2

This is UPDATE, not INSERT. it updates already inserted data.

pawn Код:
INSERT INTO table_name ( field1, field2,...fieldN ) VALUES( value1, value2,...valueN )
and
pawn Код:
UPDATE table_name SET column1=value, column2=value2 WHERE some_column=some_value
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Messages In This Thread
SQL issue. - by iGetty - 01.12.2012, 09:55
Re: SQL issue. - by Konstantinos - 01.12.2012, 10:08
Re: SQL issue. - by iGetty - 01.12.2012, 11:06
Re: SQL issue. - by Konstantinos - 01.12.2012, 11:16
Re: SQL issue. - by Ballu Miaa - 01.12.2012, 11:32
Re: SQL issue. - by iGetty - 01.12.2012, 11:34
Re: SQL issue. - by Konstantinos - 01.12.2012, 11:39
Re: SQL issue. - by iGetty - 01.12.2012, 11:40
Re: SQL issue. - by iGetty - 01.12.2012, 12:04
Re: SQL issue. - by Ballu Miaa - 02.12.2012, 06:21

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