Why can't use . in macro and what means . in PAWN

Terminator3
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25.06.2012, 21:44

As in title

pawn Код:

#define X:%0.%1(%2) something

why it gives an error that it found . (dot) ?

And . (dot) in PAWN means only float value or something else?

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Why can't use . in macro and what means . in PAWN - by Terminator3 - 25.06.2012, 21:44

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