18.02.2012, 06:39
PHP код:
if(dialogid == 20)
{
if(response == 1)
{
new query[200];
GetPlayerName(playerid, pname, sizeof pname);
format(query, sizeof(query), "INSERT INTO `suggestions` (`user`, `suggestion`) VALUES ('%s','%s')",pname, inputtext);
mysql_query(query);
mysql_store_result();
}
mysql_free_result();
}