05.12.2011, 14:24
@MP2: He did show it.
Pinguinn is right, the backslash is an escaping character. To tell the compiler you actually want to use it, you need to type it twice:
Pinguinn is right, the backslash is an escaping character. To tell the compiler you actually want to use it, you need to type it twice:
pawn Код:
Textdraw1 = TextDrawCreate(618.000000, 325.000000, "\\");