[donB]

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Originally Posted by [EDT]AmanSingh123 question is solve this equation:- 3x^2 = 6x _______________________ and also it says to solve a quadratic quation you should put into this form, ax^2 + bx + c = 0 so i did:- 3x(x-2)=0 so i presumed that x would be 3 because 3x = 0 would be x = 3 to make x the subject and then i did x-2 = 0 and then i got x = 2 so my answer was x = 3 or x = 2 but in the answer book it was x = 0 or x = 2 _______ i got two but im confused why its 0 and not 3?

Your fault: You're assuming x as 3, which ain't proper. You can't multiply both sides of an equation with 0 and claim LHS = RHS. lulz.

Simple way: 3x(x-2) = 0
=> Either x = 0 or x = 2. (3!=0)