how to solve this quadratic?
#6

3xІ = 6x
<=> 3xІ - 6x = 0

D = bІ - 4.a.c = (-6)І - 4.3.0 = 36

(-b ± √D) / 2.a

<=> (6 ± 6) / 6

x1 = 2
x2 = 0


That was pretty easy.

EDIT: You already solved it. -.-
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Messages In This Thread
how to solve this quadratic? - by [EDT]AmanSingh123 - 04.10.2011, 18:18
Re: how to solve this quadratic? - by Mark™ - 04.10.2011, 18:41
Re: how to solve this quadratic? - by Hiddos - 04.10.2011, 18:47
Re: how to solve this quadratic? - by Vince - 04.10.2011, 18:47
Re: how to solve this quadratic? - by [EDT]AmanSingh123 - 04.10.2011, 18:54
Re: how to solve this quadratic? - by RyDeR` - 04.10.2011, 19:04
Re: how to solve this quadratic? - by Mark™ - 04.10.2011, 19:08
Re: how to solve this quadratic? - by CaHbKo - 04.10.2011, 19:15
Re: how to solve this quadratic? - by donB - 04.10.2011, 20:00
Re: how to solve this quadratic? - by THE_KNOWN - 05.10.2011, 03:30

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