[Banditukas]

Hi,

If player in dialog which is input type write anything it will be null? i can check

Код:

if( isnull( inputtext ) )
{

}

??

[M4D]

pawn Код:

if(strlen(inputtext) < 1) Do Something..

https://sampwiki.blast.hk/wiki/Strlen

[UltraScripter]

this is not good he will get tag mistakes warrning

[Alvord]

This is what I normally use:

pawn Код:

if(!inputtext)
{
 // your code here
}

[TheSnaKe]

You can use Strlen, but i suggest to you to use what Alvord said.

[CutX]

Quote:

Originally Posted by UltraScripter this is not good he will get tag mistakes warrning

why?
a tag mismatch occurs when...

Quote:

Originally Posted by PAWNlang -assigning to a tagged variable a value that is untagged or that has a different tag -the expressions on either side of a binary operator have different tags - in a function call, passing an argument that is untagged or that has a different tag than what the function argument was defined with - indexing an array which requires a tagged index with no tag or a wrong tag name

i dont see how the strlen solution would trigger that... enlighten me please

Quote:

Originally Posted by TheSnaKe You can use Strlen, but i suggest to you to use what Alvord said.

totally wrong, just wrong.

this will throw error 33

Quote:

error 033: array must be indexed...

Quote:

Originally Posted by PAWNlang An array as a whole cannot be used in a expression; you must indicate an element of the array between square brackets

the solution with strlen is also not the best (it works though)

what you should do is check if the 1st real element is already the end of the string (EOS)

pawn Код:

if(inputtext[0] == EOS) //some code here

np

[Banditukas]

Thanks.

[Banditukas]

If player write a space and then text? " hello"

if(inputtext[0] == EOS) //some code here

This mean that this check is == EOS or != EOS?

[CutX]

Quote:

Originally Posted by Banditukas If player write a space and then text? " hello" if(inputtext[0] == EOS) //some code here This mean that this check is == EOS or != EOS?

a space is a space (32, to be exact) and no EOS
EOS is basically the "null-char"
this: '\0'
(its still only 1 char even though its '\' and '0')

so if inputtext is: " hello"
the control structure would look like
if(32 == EOS)

but 32 is not EOS so it'll result in false

[Vince]

Or just use isnull, correctly demonstrated in the first post. Why must everything be so difficult?