[Salim_Karaja]

I've create math system, and I faced a problem .
The admin creating an exercise .
but its a string, I mean how im extracting the answer from string like this:

pawn Код:

"18+1-8"

remember its a string .

[mastermax7777]

https://sampwiki.blast.hk/wiki/Strval

[Salim_Karaja]

Quote:

Originally Posted by mastermax7777 https://sampwiki.blast.hk/wiki/Strval

what about all the math signs, like "+", "-" ..

[Rock]

Strval

EDIT:
Nevermind, too late..

[Misiur]

Well, you should think about that earlier and store result. Otherwise you have to write own parser, or use regex

[Konstantinos]

There is a way.

pawn Код:

// Normal split function, I just added a second delimiter
stock split(const strsrc[], strdest[][], delimiter1, delimiter2)
{
    new i, li;
    new aNum;
    new len;
    while(i <= strlen(strsrc))
    {
        if((strsrc[i] == delimiter1 || strsrc[i] == delimiter2)|| i == strlen(strsrc))
        {
            len = strmid(strdest[aNum], strsrc, li, i, 128);
            strdest[aNum][len] = 0;
            li = i+1;
            aNum++;
        }
        i++;
    }
    return 1;
}

pawn Код:

main( )
{
    new
        maths_text[ 15 ],
        number_coords[ 3 ][ 3 ],
        tmpstr[ 32 ]
    ;
    format( maths_text, sizeof( maths_text ), "18-1+8" );
    split( maths_text, number_coords, '+', '-' );
    format( tmpstr, sizeof( tmpstr ), "maths: a = %s, b = %s, c = %s", number_coords[ 0 ], number_coords[ 1 ], number_coords[ 2 ] );
    print( tmpstr );
}

pawn Код:

// Output:
[23:14:36] maths: a = 18, b = 1, c = 8

[Salim_Karaja]

Quote:

Originally Posted by Dwane There is a way. pawn Код: // Normal split function, I just added a second delimiter stock split(const strsrc[], strdest[][], delimiter1, delimiter2) {     new i, li;     new aNum;     new len;     while(i <= strlen(strsrc))     {         if((strsrc[i] == delimiter1 || strsrc[i] == delimiter2)|| i == strlen(strsrc))         {             len = strmid(strdest[aNum], strsrc, li, i, 128);             strdest[aNum][len] = 0;             li = i+1;             aNum++;         }         i++;     }     return 1; } pawn Код: main( ) {     new         maths_text[ 15 ],         number_coords[ 3 ][ 3 ],         tmpstr[ 32 ]     ;     format( maths_text, sizeof( maths_text ), "18-1+8" );     split( maths_text, number_coords, '+', '-' );     format( tmpstr, sizeof( tmpstr ), "maths: a = %s, b = %s, c = %s", number_coords[ 0 ], number_coords[ 1 ], number_coords[ 2 ] );     print( tmpstr ); } pawn Код: // Output: [23:14:36] maths: a = 18, b = 1, c = 8

thank you so much !!!!!!!!!!!!!!!!!!!!!!!!

[Konstantinos]

You're welcome! I'd like to inform you though that I tested with a number with 3 digits and it fails, so the numbers should from 0 to 99. If it's equal or higher to 100, it takes the b and it's like

pawn Код:

a = 100
b = 99
result = 10099

I'll try to fix that in case you want to use greater numbers.

[Misiur]

pawn Код:

#define strcpy(%0,%1) strcat(((%0)[0]=EOS,(%0)),%1) 
Parser(str[]) {
    new result = 0, delimeter, buffer[16], capturing = -1, end = 0;
    for(new i, l = strlen(str) + 1; i != l; ++i) {
        if('0' <= str[i] <= '9') {
            if(-1 == capturing) capturing = i, end = i;
            ++end;
        } else if('+' == str[i] || '-' == str[i] || EOS == str[i]) {
            strmid(buffer, str, capturing, end);
            if(EOS != str[i]) {
                if(delimeter) {
                    result += (delimeter == '-' ? -1 : 1) * strval(buffer);             
                } else result = strval(buffer);
                delimeter = str[i];         
            }
            capturing = -1;
        }
    }
    return result;
}

main() {
    printf("%d", Parser("1823-24+15+1"));
}

Few conditions must be preserved: 1. it must start with positive number 2. no two delimeters in a row (so +-1 will fail). (I wanted to script multiplication and division, but order of operators, etc. etc. and in the end it'd get long).

#e2: Updated. Only limit is positive numbers and 15 digit number max

[mastermax7777]

or.. a much easiest way is just storing the result right from the beginning... lol