[Neil.]

pawn Код:

new SellPrice;
SellPrice = AHouseData[HouseID][HousePrice] * 0.1;

It's giving me tag mismatch errors. But when I do subtraction or addition it doesn't return that error?
Help

[admantis]

If you need to, make it a float number.

new Float:SellPrice;
SellPrice = AHouseData[HouseID][HousePrice] * 0.1;
GivePlayerMoney(playerid, (floatround(SellPrice)));

[Neil.]

Quote:

Originally Posted by admantis If you need to, make it a float number. new Float:SellPrice; SellPrice = AHouseData[HouseID][HousePrice] * 0.1; GivePlayerMoney(playerid, (floatround(SellPrice)));

Is the float conversion necessary? Tried that still, compiles with a tag mismatch error

[Sasoft]

I guess you could try this

pawn Код:

new double SellPrice;

[Neil.]

Quote:

Originally Posted by Sasoft I guess you could try this pawn Код: new double SellPrice;

That wouldn't work at all

[vIBIENNYx]

Create a new float variable and assign the value as 0.1, then keep SellPrice as a float and do the equation that way.

[kirk]

Quote:

Originally Posted by admantis If you need to, make it a float number. new Float:SellPrice; SellPrice = AHouseData[HouseID][HousePrice] * 0.1; GivePlayerMoney(playerid, (floatround(SellPrice)));

Do it this way and make sure, AHouseData[HouseID][HousePrice] its a float.

[denNorske]

As mentioned above, you could try to use a variable/define which is set to 0.1, and then attempt to try again.

like:

pawn Код:

#define value 0.1

and keep the number as a Float - ; And it should work.

[Neil.]

Quote:

Originally Posted by vIBIENNYx Create a new float variable and assign the value as 0.1, then keep SellPrice as a float and do the equation that way.

A bit of noobish here, but would I do it like this?

pawn Код:

new Float:multi;
    multi = 0.1;
    new Float:SellPrice = AHouseData[HouseID][HousePrice] * multi;
    return floatround(SellPrice);

[Sinner]

It returns a tag mismatch because HousePrice isn't a float either.

pawn Код:

new Float:SellPrice;
SellPrice = float(AHouseData[HouseID][HousePrice]) * 0.1;