[mongi]

So I'm trying to pass a variable by reference to a function using SetTimerEx and I'm just getting a messy result.
I cannot find where I fucked up and I searched about this and didn't find a thing, Help?

PHP код:

new TEST = 5;
forward decrease(&n);
public decrease(&n)
{
    printf("%i", n);
}
public OnGameModeInit()
{
    SetTimerEx("decrease", 1000, true, "i", TEST);
    return 1;
} 


Console:

PHP код:

[22:19:20] 33554432
[22:19:21] 33554432
[22:19:22] 33554432
[22:19:23] 33554432
[22:19:24] 33554432
[22:19:26] 33554432
[22:19:27] 33554432
[22:19:28] 33554432
[22:19:29] 33554432
[22:19:30] 33554432
[22:19:31] 33554432
[22:19:32] 33554432
[22:19:33] 33554432 


[kovac]

PHP код:

new TEST = 5;
forward decrease();
public decrease()
{
    TEST--;
    printf("%i", TEST);
    return 1;
}
public OnGameModeInit()
{
    SetTimer("decrease", 1000, true);
    return 1;
} 


Is this what you want to do? I might misunderstood.

Edit:
Or maybe like this:

PHP код:

new TEST = 5;
forward decrease(amount);
public decrease(amount)
{
    TEST -= amount;
    printf("%i", TEST);
    return 1;
}
public OnGameModeInit()
{
    new amount = 1;
    SetTimerEx("decrease", 1000, true, "i", amount);
    return 1;
} 


[jasperschellekens]

format a string before printing it to get the right value.

PHP код:

new TEST = 5; 
forward decrease(&n); 
public decrease(&n) 
{ 
    new str[128];
    format(str, sizeof(str), "%i", n);
    printf(str); 
} 
public OnGameModeInit() 
{ 
    SetTimerEx("decrease", 1000, true, "i", TEST); 
    return 1; 
} 


[Jefff]

Remove & mongi

[mongi]

Quote:

Originally Posted by jasperschellekens format a string before printing it to get the right value. PHP код: new TEST = 5;  forward decrease(&n);  public decrease(&n)  {      new str[128];     format(str, sizeof(str), "%i", n);     printf(str);  }  public OnGameModeInit()  {      SetTimerEx("decrease", 1000, true, "i", TEST);      return 1;  }

Still the same, It doesn't even print the correct value.



@kovac

Later on I'll have more variables which I would like to start decreasing 1 till they reach 0 so I want to pass the var. which i'm going to decrease to the function.
Doing it manually works

PHP код:

decrease(TEST); 


but I need it via a timer.

[NaS]

Public functions that have arguments which are passed by reference expect a variable (or array) as input, not a number.

If you do

Код:

decrease(5);

the compiler will give you an error:

Quote:

error 035: argument type mismatch (argument 1)

And that's basically what SetTimerEx does - the timer does NOT pass the "TEST" variable like you expected it to do, it attempts to pass its value (5) which does not work.

[Nero_3D]

You can if you pass the correct address, for example by using ref from amx_memory

PHP код:

SetTimerEx("decrease", 1000, true, "i", ref(TEST)); 


SetTimerEx is just limited to global / static variables, local variables would be out of scope
CallLocalFunction works also with local ones

[mongi]

Quote:

Originally Posted by Nero_3D You can if you pass the correct address, for example by using ref from amx_memory PHP код: SetTimerEx("decrease", 1000, true, "i", ref(TEST));  SetTimerEx is just limited to global / static variables, local variables would be out of scope CallLocalFunction works also with local ones

Passing the address to the function using ref fixed it, I guess the function kept taking "TEST"'s value and considered it as an address which just messed up.