[iKevin]

http://straccicompany.tk/ucp/?p=login

hi guys, im testing out some sorta ucp and it outputs a warning, deprecation, error, whatever.. can you tell me what's it for and what do I have to change to fix it?

thanks in advance

[Meller]

You should use a newer tutorial, but just because you wont; Simply change mysql_ to mysqli_

[iKevin]

i tried that, whole site turned into errors and it kept refreshing itself constantly

edit; changed mysql_ to mysqli_ now, check the site now..
http://straccicompany.tk/ucp/

[iKevin]

anyone?

[Luis-]

Show the mysqli_select_db & mysqli_error code.

[iKevin]

Код:

<?php

////\\\\\\\\\\\\\\\\\\\\\\EDIT The Below Variables\\\\\\\\\\\\\\\\\
////\\\\\\\\\\\\\\\\\\\ONLY EDIT WITHIN THE QUOTATION MARKS ("")\\\
//
$servername = "n10.ultra-h.com"; //Server name (usually "localhost")
$database = "port_5930";    //Database name (often username_databasename)
$username = "port_5930";        //User name for MySQL Database
$password = "*******";          //Password for MySQL User name
//
//// \\\\\\\\\\\\\\\\\\\\\\\DO NOT EDIT BELOW\\\\\\\\\\\\\\\\\\\\\\\
//
$connect = mysqli_connect($servername,$username,$password);
    mysqli_select_db($database, $connect) or die(mysqli_error());

?>

so here's the whole config.php i hope it helps

thanks in advance

[Eloy]

Update

Try Check Parameter function mysqli_connect

PHP код:

<?php
$con = mysqli_connect("HOST", "USER", "PASSWORD", "DBNAME");

if (!$con) {
    echo "Error: Mysql Conection." . PHP_EOL;
    exit;
}

echo "Ready: Success " . PHP_EOL;

?>

[Macronix]

"mysqli_select_db" asks for a database name (string) and you gave that function an integer ($connect).
The first parameter should be "$connect" and the second parameter "$database":

PHP код:

<?php
////\\\\\\\\\\\\\\\\\\\\\\EDIT The Below Variables\\\\\\\\\\\\\\\\\
////\\\\\\\\\\\\\\\\\\\ONLY EDIT WITHIN THE QUOTATION MARKS ("")\\\
//
$servername = "n10.ultra-h.com"; //Server name (usually "localhost")
$database = "port_5930";    //Database name (often username_databasename)
$username = "port_5930";        //User name for MySQL Database
$password = "*******";          //Password for MySQL User name
//
//// \\\\\\\\\\\\\\\\\\\\\\\DO NOT EDIT BELOW\\\\\\\\\\\\\\\\\\\\\\\
//
$connect = mysqli_connect($servername,$username,$password);
    mysqli_select_db($connect, $database) or die(mysqli_error($connect));
?>

You could also combine it directly with "mysqli_connect":

PHP код:

<?php
////\\\\\\\\\\\\\\\\\\\\\\EDIT The Below Variables\\\\\\\\\\\\\\\\\
////\\\\\\\\\\\\\\\\\\\ONLY EDIT WITHIN THE QUOTATION MARKS ("")\\\
//
$servername = "n10.ultra-h.com"; //Server name (usually "localhost")
$database = "port_5930";    //Database name (often username_databasename)
$username = "port_5930";        //User name for MySQL Database
$password = "*******";          //Password for MySQL User name
//
//// \\\\\\\\\\\\\\\\\\\\\\\DO NOT EDIT BELOW\\\\\\\\\\\\\\\\\\\\\\\
//
$connect = mysqli_connect($servername,$username,$password,$database);
// Check connection
if (mysqli_connect_errno())
{
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
?>

[iKevin]

Quote:

Originally Posted by Macronix "mysqli_select_db" asks for a database name (string) and you gave that function an integer ($connect). The first parameter should be "$connect" and the second parameter "$database": PHP код: <?php ////\\\\\\\\\\\\\\\\\\\\\\EDIT The Below Variables\\\\\\\\\\\\\\\\\ ////\\\\\\\\\\\\\\\\\\\ONLY EDIT WITHIN THE QUOTATION MARKS ("")\\\ // $servername = "n10.ultra-h.com"; //Server name (usually "localhost") $database = "port_5930";    //Database name (often username_databasename) $username = "port_5930";        //User name for MySQL Database $password = "*******";          //Password for MySQL User name // //// \\\\\\\\\\\\\\\\\\\\\\\DO NOT EDIT BELOW\\\\\\\\\\\\\\\\\\\\\\\ // $connect = mysqli_connect($servername,$username,$password);     mysqli_select_db($connect, $database) or die(mysqli_error($connect)); ?> You could also combine it directly with "mysqli_connect": PHP код: <?php ////\\\\\\\\\\\\\\\\\\\\\\EDIT The Below Variables\\\\\\\\\\\\\\\\\ ////\\\\\\\\\\\\\\\\\\\ONLY EDIT WITHIN THE QUOTATION MARKS ("")\\\ // $servername = "n10.ultra-h.com"; //Server name (usually "localhost") $database = "port_5930";    //Database name (often username_databasename) $username = "port_5930";        //User name for MySQL Database $password = "*******";          //Password for MySQL User name // //// \\\\\\\\\\\\\\\\\\\\\\\DO NOT EDIT BELOW\\\\\\\\\\\\\\\\\\\\\\\ // $connect = mysqli_connect($servername,$username,$password,$database); // Check connection if (mysqli_connect_errno()) {     echo "Failed to connect to MySQL: " . mysqli_connect_error(); } ?>

i tried that before

[BroZeus]

what YOU are doing :

Quote:

mysqli_select_db($database, $connect) or die(mysqli_error());

What it SHOULD be :

Quote:

mysqli_select_db($connect, $database) or die(mysqli_error());

$connect is first parameter not $db !!