[ScIrUsna]

Hi,

Код:

stock GetWeaponNameEx(weaponid, weapon[], len = sizeof(weapon))
{
    switch(weaponid)
    {
        case 18: strcat(weapon, "Molotov Cocktail", len);
        case 44: strcat(weapon, "Night Vision Goggles", len);
        case 45:  strcat(weapon, "Thermal Goggles", len);
        default: GetWeaponName(weaponid, weapon, len);
    }
    return weapon
}

It can return string?

[ayoub001]

GetWeaponName(weaponid, const weapon[], len)

weaponid: The ID of the weapon to get the name of.
const weapon[]: An array to store the weapon's name in, passed by reference.
len :The maximum length of the weapon name to store. Should be sizeof(name).

use this

[introzen]

Quote:

Originally Posted by ScIrUsna Hi, Код: stock GetWeaponNameEx(weaponid, weapon[], len = sizeof(weapon)) { switch(weaponid) { case 18: strcat(weapon, "Molotov Cocktail", len); case 44: strcat(weapon, "Night Vision Goggles", len); case 45: strcat(weapon, "Thermal Goggles", len); default: GetWeaponName(weaponid, weapon, len); } return weapon } It can return string?

Yes, it does return the string formatted accordingly to what weaponid you input to the function.

[xTURBOx]

try this

PHP код:

stock GetWeaponNameEx(weaponid, weapon[], len = sizeof(weapon))
{
    switch(weaponid)
    {
        case 18: weapon = "Molotov Cocktail";
        case 44: weapon = "Night Vision Goggles";
        case 45: weapon = "Thermal Goggles";
        default: GetWeaponName(weaponid, weapon, len);
    }
    return weapon;
}