[Baltazar]

This simple code:

Код:

#include <a_samp>

#if defined printf
  #undef printf
#endif

main(){

}

Doesn't compile! Why!?


It seems like this line

Код:

#if defined printf

finds printf to be defined and tries to execute this line

Код:

#undef printf

but compiler emits error on this as it doesn't recognize printf as defined anymore... wtf? Explain me please

[Vince]

You can't simply "undefine" just anything. The manual says:

Quote:

#undef name Removes a text substitution macro or a numeric constant declared with const. The “name” parameter must be the macro “prefix” —the alphanumeric part of the macro. See page 93 for details and examples on text substitution.

[Baltazar]

Quote:

Originally Posted by Vince You can't simply "undefine" just anything. The manual says:

Ok, thanks; I got it. Here is one more:

Код:

#include <a_samp>

#define _FIRST print

main(){

  _FIRSTf("%s", "Test string");

}

Here is my understanting:
Pre-compiler meets #define. From now on it searches for any instance of "_FIRST" and replaces it with "print". Just like a human being would do it using text replacement tool.

But:
It doesn't work this exact way and throws an error about "_FIRSTf" being not defined. How does it work then? Sometimes it replaces chunks of code, sometimes it doesn't.

[Crayder]

- CUT -

The predecessor searches only for whole words.

To do _FIRSTf
You need to #define _FIRSTf printf

[Baltazar]

Quote:

Originally Posted by Crayder This line, #undef printf, undefined the printf. So it will not be defined, it's pretty self explanatory.

It doesn't. Compiler throws an error, that such a constant "printf" doesn't exist and thus can't be undefined.

[Crayder]

Quote:

Originally Posted by Baltazar It doesn't. Compiler throws an error, that such a constant "printf" doesn't exist and thus can't be undefined.

printf is not a constant in the script. So it is correct. It's a native function.

[Baltazar]

Quote:

Originally Posted by Crayder printf is not a constant in the script. So it is correct. It's a native function.

But well, this line

Код:

#if defined printf

finds "printf" to be defined although it's not a constant. Anyway, you are right and I kind of got it

[Threshold]

pawn Код:

#define _FIRSTf printf

Works fine for me.

Код:

doesn't exist and thus can't be undefined.

Those are two different things. They either exist and are defined, or do not exist and are undefined. You can't have both.

[Crayder]

Quote:

Originally Posted by Baltazar finds "printf" to be defined although it's not a constant. Anyway, you are right and I kind of got it

Aha, I don't think I'm right completely. I think I should take another look at the manual, you should as well.

http://www.compuphase.com/pawn/Pawn_Language_Guide.pdf

[Baltazar]

Quote:

Originally Posted by Threshold Код: doesn't exist and thus can't be undefined. Those are two different things. They either exist and are defined, or do not exist and are undefined. You can't have both.

By saying "can't be undefined" I mean "you can't undefine it".