[Shabi RoxX]

Hi guys I am learning mysql but I am getting a problem here.

Код:

E:\Shabi\server\test\gamemodes\test.pwn(139) : error 035: argument type mismatch (argument 1)

Код:

138:new adminlvl;
139:mysql_fetch_field_row(adminlvl,"adminlevel");

[Shabi RoxX]

Any one please , help fast....

[thimo]

What Mysql plugin are you using?

[Shabi RoxX]

MySQL Plugin R6-2 BY BlueG > https://sampforum.blast.hk/showthread.php?tid=56564

[Shabi RoxX]

Any idea Plzzzz

[MP2]

The adminlvl variable should be a string.

new adminlvl[5];

[Shabi RoxX]

Now what about my INT??

Код:

else if(rows == 1)
	{
		new adminlvl[5];
		mysql_fetch_field_row(adminlvl,"adminlevel");
		P_Var[playerid][p_Adminlevel] = adminlvl; //line 154
	}

Код:

E:\Shabi\server\test\gamemodes\test.pwn(154) : error 006: must be assigned to an array

[T0pAz]

Use mysql_fetch_int(); - Returns the int.

[AndreT]

He obviously uses the code in a loop, so using mysql_fetch_int is out of the question.

Something like this won't work for obvious reasons:

pawn Код:

new adminlvl[5];
P_Var[playerid][p_AdminLevel] = adminlvl;

What you need to do is use strval, which "converts" string into an integer!

pawn Код:

P_Var[playerid][p_AdminLevel] = strval(adminlvl);

[Shabi RoxX]

Thanks for helping.....