[DeathOnaStick]

Heyho!
I've got a little question here. First an example:

pawn Код:

Var1=4;
Var2=4;

Var3=0;

while(Var1==Var2)
{
if(Var3>=Var2)break;
Var3++;
}

Var4=Var3;

1. Will the code after the loop be executed, when the loop is stopped?
2. Does it work to use "return 0;" for stopping a loop?
3. If yes, will the code after the loop be executed?
4. Is there a other way to stop the loop, except changing one of the "while"-conditions (here Var1 or Var2)?

Thanks,
DeathOnaStick

[ray187]

This is an endless loop as
Var1=Var2
is always true (you assign Var2 to Var1).

What you want to do is
Var1==Var2
which compares both values.

The code after the loop is executed when the loop has ended.

"break;" is the command to stop a loop.

[DeathOnaStick]

Quote:

Originally Posted by ray187 This is an endless loop as Var1=Var2 is always true (you assign Var2 to Var1). What you want to do is Var1==Var2 which compares both values. The code after the loop is executed when the loop has ended. "break;" is the command to stop a loop.

True, i just forgot putting the "=" double .

[ray187]

All questions answered?

[DeathOnaStick]

Does the code after the loop gets executed when i stop it with "break"?

[ray187]

Quote:

The code after the loop is executed when the loop has ended.

So yeah as the loop ends when using break.

[DeathOnaStick]

Does the loop end, too, when i use "return 0;" instead of break?

[Rac3r]

I think returning 0 wouldn't really help. Break will terminate the loop, return will terminate the function.

Example:

Код:

foreach(Player,i)
{
  if( i != -1)break; // will break
}
SetPlayerHealth(playerid, 0.0); // and set player health to 0

Код:

foreach(Player,i)
{
  if( i != -1)return 0; // will halt
}
SetPlayerHealth(playerid, 0.0); // set player health to 0 will not be called

[ray187]

.

[MadeMan]

break and return both end the loop.

With break the code after the loop will be executed, but with return the code after the loop will not be executed.