[UsaBoy91]

I made a function , but i need it as a macro ...

pawn Код:

Checkx(string[])
{
    if(!strcmp(string,"Drive",true) || !strcmp(string,"Fly",true)) return 1;
    return 0;
}

This is good , but if i try to make it macro ... :

pawn Код:

#define Checkx(%0) if(!strcmp(%0,"Drive",true) || !strcmp(%0,"Fly",true)) return 1; else return 0;

I get errors ...

[¤Adas¤]

pawn Код:

#define Checkx(%0) return !strcmp(%0, "Drive", true) || !strcmp(%0, "Fly", true);

Try this, maybe it will work

[UsaBoy91]

somebody else ?

[Jefff]

Try this

Код:

#define Checkx(%0) (!strcmp(%0, "Drive", true) || !strcmp(%0, "Fly", true)) ? 1 : 0;

[¤Adas¤]

Quote:

Originally Posted by Jefff Try this Код: #define Checkx(%0) (!strcmp(%0, "Drive", true) || !strcmp(%0, "Fly", true)) ? 1 : 0;

It depends on this func. usage.

[IownU]

Use #

#%0

I recommend starting from %1 in defines though.


EDIT: Oh, so that wasn't the problem. Uhm, defines can only use one " if() something; "
Why don't you just keep the function and make it like this then:

Код:

#define Checkx(%1); FunctionCheckx(#%1);

Checkx(noob);

Well you get the idea..

[rs.pect]

pawn Код:

#define Checkx(%0) (!strcmp(%0, "Drive", true) || !strcmp(%0, "Fly", true))

[legodude]

cant use spaces in a define do:

#define funcx \
funcwhatitdoes

[rs.pect]

Can't use spaces in the pattern - Checkx(%0), but can in the replacement part - check it.

[The_Moddler]

pawn Код:

#define Checkx(%0) \
    (!strcmp((%0),"Drive",true)) || (!strcmp((%0),"Fly",true))

Try it out.