[robert4049]

How can i get rid of the error?

Код:

C:\Users\Robert\Desktop\VortexRoleplay\gamemodes\VortexRoleplay.pwn(9789) : warning 219: local variable "string" shadows a variable at a preceding level
Pawn compiler 3.2.3664	 	 	Copyright © 1997-2006, ITB CompuPhase


1 Warning.

pawn Код:

new pname[MAX_PLAYER_NAME], string[22 + MAX_PLAYER_NAME];
    GetPlayerName(playerid, pname, sizeof(pname));
    format(string, sizeof(string), "%s has joined the server", pname);
    SendClientMessageToAll(0xAAAAAAAA, string);

[Rocky Balboa]

there may be two , new string[22+MAX_PLAYER_NAME]; in the same callback , or what ever that is called

[Carlton]

pawn Код:

new pname[MAX_PLAYER_NAME], stringz[46];
GetPlayerName(playerid, pname, sizeof(pname));
format(stringz, sizeof(stringz), "%s has joined the server", pname);
SendClientMessageToAll(0xAAAAAAAA, stringz);

You created the variable string twice, make sure you don't fall for that again.

[Las Venturas CNR]

Try just using

pawn Код:

new string[64], pName[MAX_PLAYER_NAME];
    GetPlayerName(playerid,pName,MAX_PLAYER_NAME);
    format(string,sizeof string,"%s has joined the server.",pName);
    SendClientMessageToAll(0xFFFFFFAA,string);

[Carlton]

Quote:

Originally Posted by Las Venturas CNR Try just using pawn Код: new string[64], pName[MAX_PLAYER_NAME];     GetPlayerName(playerid,pName,MAX_PLAYER_NAME);     format(string,sizeof string,"%s has joined the server.",pName);     SendClientMessageToAll(0xFFFFFFAA,string);

That wouldn't work because you're still making the error occur.

[Las Venturas CNR]

Quote:

Originally Posted by Carlton That wouldn't work because you're still making the error occur.

Huh...? Umm... wonder why thats on Wiki then, strange...


go to https://sampwiki.blast.hk/wiki/OnPlayerConnect and look at the example, lol.

[Carlton]

Quote:

Originally Posted by Las Venturas CNR Huh...? Umm... wonder why thats on Wiki then, strange... go to https://sampwiki.blast.hk/wiki/OnPlayerConnect and look at the example, lol.

If you know what the warning means then don't reply, but obviously you don't. It means you defined a variable twice. He used string twice in a callback. That wiki link has Nothing to do with this solving this.

[Las Venturas CNR]

Quote:

Originally Posted by Carlton If you know what the warning means then don't reply, but obviously you don't. It means you defined a variable twice. He used string twice in a callback. That wiki link has Nothing to do with this solving this.

I misread something. Sorry, please excuse me...

[John_F]

You have 2 of the same variable.
Delete the 1 on the lowest level, AKA the 1 that is pointed out by the warning.