[Tigerkiller]

Hello Community.
I tryed to Create my Own MySQL Login/Registersystem but when i try to register it gives me an syntax error:

Код:

[Mon Jan 30 03:36:25 2012] Error (0): Failed to exeute query. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Alter, Geschlecht, Muted, Freezed, Tutorial) VALUES ('[GRW]Firebird','TestPasswort',' at line 1.

My Register Code are as following:

pawn Код:

public OnPlayerRegister(playerid,key[])
{
    printf("playerid: %i - Passwort: %s",playerid,key);
    new Name[MAX_PLAYER_NAME], Query[500], escname[MAX_PLAYER_NAME];
    GetPlayerName(playerid, Name, sizeof Name);
    mysql_real_escape_string(Name,escname);
    format(Query,sizeof Query,"INSERT INTO `Accounts` (Nickname, Passwort, Admin, Level, Respect, Geld, Handy, HandyGeld, Fraktion, Leader, Alter, Geschlecht, Muted, Freezed, Tutorial) VALUES ('%s','%s',0,1,0,20000,1,50,0,0,0,0,0,0,0)",escname,key);
    printf("%s",Query);
    mysql_query(Query);
}

Database:

Код:

CREATE TABLE `GRW`.`Accounts` (
`ID` INT( 255 ) NOT NULL AUTO_INCREMENT ,
`Nickname` VARCHAR( 30 ) NOT NULL ,
`Passwort` VARCHAR( 20 ) NOT NULL ,
`Admin` INT( 2 ) NOT NULL ,
`Level` INT( 100 ) NOT NULL ,
`Respect` INT( 100 ) NOT NULL ,
`Geld` INT( 50 ) NOT NULL ,
`Handy` INT( 2 ) NOT NULL ,
`HandyGeld` INT( 100 ) NOT NULL ,
`Fraktion` INT( 3 ) NOT NULL ,
`Leader` INT( 3 ) NOT NULL ,
`Alter` INT( 2 ) NOT NULL ,
`Geschlecht` INT( 1 ) NOT NULL ,
`Muted` INT( 1 ) NOT NULL ,
`Freezed` INT( 1 ) NOT NULL ,
`Tutorial` INT( 1 ) NOT NULL ,
PRIMARY KEY ( `ID` )
) ENGINE = MYISAM ;

Iam using Strickenkid's MySQL Plugin and i dont get any errors.
can anyone tell me whats wrong on the syntax ?

Regards Tigerkiller

[Ricop522]

pawn Код:

public OnPlayerRegister(playerid,key[])
{
    printf("playerid: %i - Passwort: %s",playerid,key);
    new Name[MAX_PLAYER_NAME], Query[500], escname[MAX_PLAYER_NAME];
    GetPlayerName(playerid, Name, sizeof Name);
    mysql_real_escape_string(Name,escname);
    format(Query,sizeof Query,"INSERT INTO `Accounts` \
    (Nickname, \
    Passwort, \
    Admin, \
    Level, \
    Respect, \
    Geld, \
    Handy, \
    HandyGeld, \
    Fraktion, \
    Leader, \
    Alter, \
    Geschlecht, \
    Muted, \
    Freezed, \
    Tutorial) \
    VALUES \
    ('%s',\
    '%s',\
    '0',\
    '1',\
    '0',\
    '20000',\
    '1',\
    '50',\
    '0',\
    '0',\
    '0',\
    '0',\
    '0',\
    '0',\
    '0')",escname,key);
    printf("%s",Query);
    mysql_query(Query);

To me is nothing wrong o-0

[MP2]

You should assign default values to fields instead of setting them in that query.

[[HiC]TheKiller]

You cannot use Alter as a field name in a query like that due to it being used to alter the table. Rename the Alter field to something else.