[Lorenc_]

Title says it all, does anyone have a solution?

[Skylar Paul]

Seems like you're going to need an algorithm.. Oh how I hate mathematics..

[Lorenc_]

Well of course I do xD, though I don't know any particular algorithm for this...

[Skylar Paul]

Quote:

Originally Posted by Lorenc_ Well of course I do xD, though I don't know any particular algorithm for this...

If I knew advanced mathematics I would help you, but I don't think I have any chance at it considering I still managed to fail Geometry, lol. Good luck finding someone.

[Shadoww5]

Try this:

PHP код:

stock GetCenterPoint(Float:Pos1, Float:Pos2)
{
    new Float:dist;
    if(Pos1 > Pos2) { dist = Pos1+((Pos1-Pos2)/2); }
    else { dist = Pos2+((Pos2-Pos1)/2); }
    return dist;
} 


How to use:

PHP код:

public OnPlayerDeath(playerid, killerid, reason)
{
    new Float:F[3], Float:FF[3];
    GetPlayerPos(playerid, F[0], F[1], F[2]);
    GetPlayerPos(killerid, FF[0], FF[1], FF[2]);
    new Float:X = GetCenterPoint(F[0], FF[0]);
    new Float:Y = GetCenterPoint(F[1], FF[1]);
    printf("Medium point: %f X & %f Y", X, Y);
    return 1;
} 


[Lorenc_]

Quote:

Originally Posted by Shadoww5 Try this: PHP код: stock GetCenterPoint(Float:Pos1, Float:Pos2) {     new Float:dist;     if(Pos1 > Pos2) { dist = Pos1+((Pos1-Pos2)/2); }     else { dist = Pos2+((Pos2-Pos1)/2); }     return dist; }  How to use: PHP код: public OnPlayerDeath(playerid, killerid, reason) {     new Float:F[3], Float:FF[3];     GetPlayerPos(playerid, F[0], F[1], F[2]);     GetPlayerPos(killerid, FF[0], FF[1], FF[2]);     new Float:X = GetCenterPoint(F[0], FF[0]);     new Float:Y = GetCenterPoint(F[1], FF[1]);     printf("Medium point: %f X & %f Y", X, Y);     return 1; }

Not for that, I want to find the center location from the X, Y to the other X, Y.

stock GetCenterPoint(Float:Pos1_X, Float:Pos1_Y, Float:Pos2_X, Float:Pos2_Y)

[Calgon]

Is this relevant?

[Mauzen]

Here it is, isnt that hard:

pawn Код:

stock GetMiddlePos(Float:x_1, Float:y_1, Float:x_2, Float:y_2, &Float:x_mid, &Float:y_mid)
{
    x_mid = (x_1 + x_2) / 2;    // Arithmetic mean value is all you need
    y_mid = (y_1 + y_2) / 2;
}

[Sasino97]

I studied analytic geometry at school:

SR = Square Root
| = Absolute value
**2 = Squared
x1, x2, y1, y2 = The variables

PHP код:

SR[|x1-x2|**2 - |y1-y2|**2] 


-------------

EDIT: Wrong, thats the formula to find the distance , sorry.

The right formula is

PHP код:

[(x1+x2)/2], [(y1+y2)/2] 


[Lorenc_]

Quote:

Originally Posted by Mauzen Here it is, isnt that hard: pawn Код: stock GetMiddlePos(Float:x_1, Float:y_1, Float:x_2, Float:y_2, &Float:x_mid, &Float:y_mid) {     x_mid = (x_1 + x_2) / 2;    // Arithmetic mean value is all you need     y_mid = (y_1 + y_2) / 2; }

Ill try this out and post my results (Edit this post), yes calgon, thats what i was looking for.