[AlexandA]

Hey, i have a problem with strmid.
I want to take the string "s" to the string "JobInfo[id][Name]" But when i print JobInfo[id][Name], it prints <null>.

Код:

strmid(JobInfo[Missions][Name],s,0,strlen(JobInfo[Missions][Name]),strlen(JobInfo[Missions][Name]));

[MenaceX^]

I didn't even look at the code but try format.

[AlexandA]

I tried it allready, but i became a few of errors:

Код:

format(JobInfo[Missions][Name],sizeof(JobInfo[Missions][Name]),"%s",Dateien[d]);

Quote:

D:\Dokumente und Einstellungen\Alexander\Eigene Dateien\Work..pwn(382) : error 001: expected token: "]", but found "-identifier-" D:\Dokumente und Einstellungen\Alexander\Eigene Dateien\Work.pwn(382) : warning 215: expression has no effect D:\Dokumente und Einstellungen\Alexander\Eigene Dateien\Work.pwn(382) : error 001: expected token: ";", but found "]" D:\Dokumente und Einstellungen\Alexander\Eigene Dateien\Work..pwn(382) : error 029: invalid expression, assumed zero D:\Dokumente und Einstellungen\Alexander\Eigene Dateien\Work..pwn(382) : fatal error 107: too many error messages on one line

Edit: Okay i make now:

Код:

format(JobInfo[Missions][Name],60,"%s",Dateien[d]);

and it compiles without a problem or errors.


Thanks for help and sorry for my bad english

[MenaceX^]

You also can to not make the %s.

pawn Код:

format(JobInfo[Missions][Name],sizeof(something),Dateien[d]);

[AlexandA]

oh thanks. I thought i need the %s. Thanks for your tip.