[MadGuy]

Hi Guyz,I want if the player is registered and he join backs i want "Welcome back,[Player Name Here]"in that login dialog box,But getting three same warnings,"Warning 202:number of arguments does not match definition".Help me..

Код:

ShowPlayerDialog(playerid, DIALOG_LOGIN, DIALOG_STYLE_INPUT,""COL_WHITE"Login",""COL_WHITE"Welcome back,%s",""COL_WHITE"Type your password below to login.","Login","Quit",PlayerInfo[playerid][pName],playerid);

[Kane]

You need to format it.

PHP код:

new
    str[128]
;
format(str, sizeof(str), ""COL_WHITE" Welcome back %s, Type your password below to login.", PlayerInfo[playerid][pName]);
ShowPlayerDialog(playerid, DIALOG_ID, DIALOG_STYLE, "caption", str, "Button 1", "Button 2"); 


[MadGuy]

Quote:

Originally Posted by Arthur Kane You need to format it. PHP код: new     str[128] ; format(str, sizeof(str), ""COL_WHITE" Welcome back %s, Type your password below to login.", PlayerInfo[playerid][pName]); ShowPlayerDialog(playerid, DIALOG_ID, DIALOG_STYLE, "caption", str, "Button 1", "Button 2");

Arthur it is not showing player name in the box,My Code:

Код:

format(str, sizeof(str), ""COL_WHITE" Welcome back %s, Type your password below to login.", PlayerInfo[playerid][pName]);
	ShowPlayerDialog(playerid, DIALOG_LOGIN, DIALOG_STYLE_INPUT, ""COL_WHITE"Login", str, "Login", "Quit");

screenshot:

[fuckingcruse]

Код:

new str[128], pname[MAX_PLAYER_NAME];
GetPlayerName(playerid,pname,sizeof(pname));
format(str, sizeof(str), ""COL_WHITE" Welcome back %s, Type your password below to login.", pname); 

ShowPlayerDialog(playerid, DIALOG_LOGIN, DIALOG_STYLE_INPUT,""COL_WHITE"Login",str,""COL_WHITE"Type your password below to login.","Login","Quit");

[MadGuy]

It's Fixed,Thank you Guyz