[PepsiCola23]

Hello guys,i came back and i started to script again but i kinda forgot something.

So i got some cmd like /getgift that players can get after 50 hours on server.
I made the function that counts the hours,everything is ok.
I make a progressbar to show how much you have til` you can /getgift,but how can i check if the player already used the CMD? so they cant use the cmd over and over after they reached 50 level.

i Though about making a new column in mysql with Gift and 2 options Yes/No
and when the player connects,a function checks if the player didnt use the cmd,and then it shows him the progress bar.......or,if he already used it [ yes on mysql database] it doesnt show it to him.
how can i make this ? any ideas?

[Pearson]

Hello.
Add this in your mysql database

PHP код:

pUsedgift 


Then add this in your playerdata enum something like this

PHP код:

enum PlayerInfo
{
pUsedgift
} 


Then create function which get data from sql.
Then add this in head of cmd.

PHP код:

if(PlayerInfo[playerid][pGiftused] != 1)
{
 //YOUR CODE
} 


[PepsiCola23]

ok i did this but it works,but what is the difference between

PHP код:

if(PlayerInfo[playerid][pGiftused] != 1) return ..... code 


and

PHP код:

if(PlayerInfo[playerid][pGiftused] == 1) return .... 


??

[AndySedeyn]

By returning a value in an if statement (and anywhere else in a function really), you:

1. terminate the function that the if-statement is in (when the if-statement is executed);
2. can treat everything outside that if statement as the else statement; i.e:
   
   PHP код:

   someFunction() {
    if(someCondition)
        // Terminate the function 
        return true;
    // code under this is ONLY executed when that if statement evaluates to false, thus it can be considered the 'else' statement for that if statement.
    return false;
} 

   One could debate that, if the return value in the if statement is the same as the function's end return value, then the else statement should be used:
   
   PHP код:

   someFunction() {
    if(someCondition)
        // Terminate the function 
        return true;
    // code
    return true; // return value is true which is the same as in the if block
} 

   PHP код:

   someFunction() {
    if(someCondition) {
        // code 
    }
    else {
        // code
    }
    return true;
} 


I think that's what you meant.

[AjaxM]

Quote:

Originally Posted by PepsiCola23 ok i did this but it works,but what is the difference between PHP код: if(PlayerInfo[playerid][pGiftused] != 1) return ..... code  and PHP код: if(PlayerInfo[playerid][pGiftused] == 1) return ....  ??

PHP код:

if(PlayerInfo[playerid][pGiftused] != 1) return ... 


This code means: If the the player's pGiftused value is NOT 1 then it will return ...

PHP код:

if(PlayerInfo[playerid][pGiftused] == 1) return .... 


This code means: If the player's pGiftused value is equal to 1 then it will return ....

That's all!