variables - Printable Version

variables - Printable Version

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variables - Khelif - 25.08.2009

Код:

new variable[3];

pawn Код:

if(variable[!2] == 1)
{
  ....
}

does that mean if the variable is other than 2? its basically then 0 and 1?

Re: variables - Paladin - 25.08.2009

I think it does.
Why not try it for yourself?