Will this timer wait? (order of operations)

Will this timer wait? (order of operations) - Printable Version

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Will this timer wait? (order of operations) - ShOoBy - 30.01.2019

Hi, please help me understand pawn's order of operations by considering the following code:

Код:

stock FirstFunction() {

	SecondFunction();
	print("F1");
}

stock SecondFunction() {

	print("F2");
	SetTimer("ThirdFunction", 1, false);
}

stock ThirdFunction() {

	print("F3");
}

So it's not that hard to understand that "F2" will be printed before "F1", but what about "F3"?
Will the order always be "F2 F1 F3", or maybe due to the low 1 tick value, the timer callback will RARELY be executed first, so that "F3" is printed before returning to the original function and printing "F1".

Additionally, what if instead of a single print("F1") I would do a lot more, will that delay it enough so that the timer is executed before the first function finishes?

In a nutshell, how reliable it is that the timer will always run last?