if is not working - Printable Version

if is not working - Printable Version

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+--- Thread: if is not working (/showthread.php?tid=646173)

if is not working - Marllun - 12.12.2017

I already tried several ways but it does not work, it always goes to the next dialog.

PHP код:



    if(dialogid == 51)

    {


        if(response)

        {

            if(strlen(inputtext) < 0 && strlen(inputtext) > 2 && IsNumeric(inputtext))

            {

            ShowPlayerDialog(playerid, 2, DIALOG_STYLE_LIST, "{33CCFF}Customizaзхes", "{FFFF00}Veiculos customizados\n{33AA33}Clima\n{33AA33}Tempo da corrida\nTempo para iniciar a corrida\ntempo para os jogadores entra na corrida\nCriar Carro", "Selecionar", "Cancelar");

            DOF2_SetInt(trackname,"TempoCorrida",strval(inputtext)*60000);

            }

            else

            {

            ShowPlayerDialog(playerid, 51, DIALOG_STYLE_INPUT, "Tempo da corrida", "Coloque o tempo da corrida. lembrando de 1 a 60 minutos!", "Selecionar", "");

            }


        }

        //ShowPlayerDialog(playerid, 2, DIALOG_STYLE_LIST, "{33CCFF}Customizaзхes", "{FFFF00}Veiculos customizados\n{33AA33}Clima\n{33AA33}Tempo da corrida\nTempo para iniciar a corrida\ntempo para os jogadores entra na corrida\nCriar Carro", "Selecionar", "Cancelar");

    }

Re: if is not working - RogueDrifter - 12.12.2017

Quote:

Originally Posted by Marllun

I already tried several ways but it does not work, it always goes to the next dialog.

PHP код:



    if(dialogid == 51)

    {


        if(response)

        {

            if(strlen(inputtext) < 0 && strlen(inputtext) > 2 && IsNumeric(inputtext))

            {

.......

.......

PHP код:



 if(strlen(inputtext) < 0 && strlen(inputtext) > 2 && IsNumeric(inputtext))

i have no idea what this is, you literally put if the text is lower than 0 and bigger than 2
you used a case that will NEVER happen wtf is that man ? change that to:

PHP код:



 if(strlen(inputtext) > 2 && IsNumeric(inputtext))

Re: if is not working - Marllun - 12.12.2017

Did not work

PHP код:



    if(dialogid == 51)

    {


        if(response == 1)

        {

              if(strlen(inputtext) > 2 && IsNumeric(inputtext))

            {

            ShowPlayerDialog(playerid, 2, DIALOG_STYLE_LIST, "{33CCFF}Customizaзхes", "{FFFF00}Veiculos customizados\n{33AA33}Clima\n{33AA33}Tempo da corrida\nTempo para iniciar a corrida\ntempo para os jogadores entra na corrida\nCriar Carro", "Selecionar", "Cancelar");

            DOF2_SetInt(trackname,"TempoCorrida",strval(inputtext)*60000);

            }

            else

            {

            ShowPlayerDialog(playerid, 51, DIALOG_STYLE_INPUT, "Tempo da corrida", "Coloque o tempo da corrida. lembrando de 1 a 60 minutos!", "Selecionar", "");

            }


        }

        //ShowPlayerDialog(playerid, 2, DIALOG_STYLE_LIST, "{33CCFF}Customizaзхes", "{FFFF00}Veiculos customizados\n{33AA33}Clima\n{33AA33}Tempo da corrida\nTempo para iniciar a corrida\ntempo para os jogadores entra na corrida\nCriar Carro", "Selecionar", "Cancelar");

    }

Re: if is not working - RogueDrifter - 12.12.2017

show your IsNumeric and if you don't mind answering, what kind of a dialog is this? register/login..??
and in what case is this dialog shown?

Re: if is not working - Marllun - 12.12.2017

PHP код:



IsNumeric(const string[])

{

        for (new i = 0, j = strlen(string); i < j; i++)

        {

                if (string[i] > '9' || string[i] < '0') return 0;

        }

        return 1;

}

PHP код:



ShowPlayerDialog(playerid, 2, DIALOG_STYLE_LIST, "{33CCFF}Customizaзхes", "{FFFF00}Veiculos customizados\n{33AA33}Clima\n{33AA33}Tempo da corrida\nTempo para iniciar a corrida\ntempo para os jogadores entra na corrida\nCriar Carro", "Selecionar", "Cancelar");

When I select Time Racer it goes to this dialog ai I have to type from 1 to 60.But when I put anything 21124 rjerj 0 12 or $ @ @ @ it goes to list instead of back to the dialog

Re: if is not working - DarkBr - 12.12.2017

Код:

if(strlen(inputtext) < 0 && strlen(inputtext) > 2 && IsNumeric(inputtext))

Quote:

StringInteira(texto) abaixo de 0 E StringInteira(texto) acima de 2 E ValorNъmero(texto)

Nгo entendi!

Re: if is not working - Marllun - 12.12.2017

It was my mistake

Re: if is not working - RogueDrifter - 12.12.2017

oh i think now i understand, you want the dialog to only accept numbers from 1 to 60! try this code and let me know if it works.

PHP код:



 if(strlen(inputtext) > 0 && strlen(inputtext) <3 && IsNumeric(inputtext))

Re: if is not working - DarkBr - 12.12.2017

tente

Код:

if(strval(inputtext) > 2 && IsNumeric(inputtext))

Re: if is not working - RogueDrifter - 12.12.2017

Quote:

Originally Posted by DarkBr

tente

Код:

if(strval(inputtext) > 2 && IsNumeric(inputtext))

Are you stupid? first of all use English and second of all stop copying my comments you're taking irrelevant space and making the thread poster more confused!