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Turn an integer into variable? - Printable Version

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+--- Thread: Turn an integer into variable? (/showthread.php?tid=633624)


Turn an integer into variable? - YouHack - 04.05.2017

Hi,
I'm trying to use an "if" statement with "data" in this code: ( From HTTP in wiki )
PHP код:
forward MyHttpResponse(index, response_code, data[]);
 
public OnPlayerCommandText(playerid, cmdtext[])
{
    if(!strcmp("/hello",cmdtext,true))
    {
        HTTP(playerid, HTTP_GET, "kc.gd/hello.txt", "", "MyHttpResponse");
        return 1;
    }
    return 0;
}
 
public MyHttpResponse(index, response_code, data[])
{
    // In this callback "index" would normally be called "playerid" ( if you didn't get it already :) )
    new
        buffer[ 128 ];
    if(response_code == 200) //Did the request succeed?
    {
        //Yes!
        format(buffer, sizeof(buffer), "The URL replied: %s", data);
        SendClientMessage(index, 0xFFFFFFFF, buffer);
    }
    else
    {
        //No!
        format(buffer, sizeof(buffer), "The request failed! The response code was: %d", response_code);
        SendClientMessage(index, 0xFFFFFFFF, buffer);
    }
} 
and it returns:
Код:
error 033: array must be indexed (variable "databody")
example of usage:
PHP код:
if(databody == -1){ 
thanks.

Re: Turn an integer into variable? - Dignity - 04.05.2017

"databody" is an array, so you have to index it, like so:

pawn Код:
if(databody[0] == -1){
If "databody" is meant to be a string, you can just do this to check whether it's empty or not:

pawn Код:
if ( ! strlen ( databody ) ) {
// code here to be called if databody is empty
}
also i'm pretty sure an integer IS a variable lol

Re: Turn an integer into variable? - Vince - 04.05.2017

If your API always returns an integer then you can simply use strval(). Otherwise you need to use strcmp().

Re: Turn an integer into variable? - YouHack - 04.05.2017

Databody hasn't just -1, it has 0 and 1 + between 0 and 1 ( decimal ) ...

Re: Turn an integer into variable? - YouHack - 04.05.2017

Solved using strval(), thanks both.