[Ajuda] Foreach. - Printable Version
+- SA-MP Forums Archive (
https://sampforum.blast.hk)
+-- Forum: Non-English (
https://sampforum.blast.hk/forumdisplay.php?fid=9)
+--- Forum: Languages (
https://sampforum.blast.hk/forumdisplay.php?fid=33)
+---- Forum: Português/Portuguese (
https://sampforum.blast.hk/forumdisplay.php?fid=34)
+---- Thread: [Ajuda] Foreach. (
/showthread.php?tid=628097)
Foreach. -
Relaxed - 05.02.2017
Bom estou tendo problemas com essa warning.
Код:
warning 219: local variable "using_deprecated_foreach_syntax" shadows a variable at a preceding level
Atualizei tudo jб, e fica dando isso.
O Cуdigo que estou com problema:
Код:
foreach (Player, playerid) // Linha da warning.
{
GetPlayerName(playerid, name, sizeof (name));
if (!strcmp(name, string[stringPos], true, id))
{
setarg(paramPos, 0, playerid);
num = true;
break;
}
}
Como posso resolver?
Respuesta: Foreach. -
SammyJ - 05.02.2017
PHP код:
foreach (new playerid: Player) // Linha da warning.
{
GetPlayerName(playerid, name, sizeof (name));
if (!strcmp(name, string[stringPos], true, id))
{
setarg(paramPos, 0, playerid);
num = true;
break;
}
}
Re: Respuesta: Foreach. -
Relaxed - 05.02.2017
Quote:
Originally Posted by SammyJ
PHP код:
foreach (new playerid: Player) // Linha da warning.
{
GetPlayerName(playerid, name, sizeof (name));
if (!strcmp(name, string[stringPos], true, id))
{
setarg(paramPos, 0, playerid);
num = true;
break;
}
}
|
Deu certo, obrigado.