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[Ajuda] Foreach. - Printable Version

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+---- Thread: [Ajuda] Foreach. (/showthread.php?tid=628097)



Foreach. - Relaxed - 05.02.2017

Bom estou tendo problemas com essa warning.

Код:
warning 219: local variable "using_deprecated_foreach_syntax" shadows a variable at a preceding level
Atualizei tudo jб, e fica dando isso.

O Cуdigo que estou com problema:

Код:
					foreach (Player, playerid) // Linha da warning.
					{
						GetPlayerName(playerid, name, sizeof (name));
						if (!strcmp(name, string[stringPos], true, id))
						{
							setarg(paramPos, 0, playerid);
							num = true;
							break;
						}
					}
Como posso resolver?


Respuesta: Foreach. - SammyJ - 05.02.2017

PHP код:
foreach (new playeridPlayer// Linha da warning.
{
    
GetPlayerName(playeridnamesizeof (name));
    if (!
strcmp(namestring[stringPos], trueid))
    {
        
setarg(paramPos0playerid);
        
num true;
        break;
    }




Re: Respuesta: Foreach. - Relaxed - 05.02.2017

Quote:
Originally Posted by SammyJ
Посмотреть сообщение
PHP код:
foreach (new playeridPlayer// Linha da warning.
{
    
GetPlayerName(playeridnamesizeof (name));
    if (!
strcmp(namestring[stringPos], trueid))
    {
        
setarg(paramPos0playerid);
        
num true;
        break;
    }

Deu certo, obrigado.