is date exist. - Printable Version

is date exist. - Printable Version

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+--- Thread: is date exist. (/showthread.php?tid=626384)

is date exist. - MerryDeer - 14.01.2017

Hi,

How to check is specific date, is exist?, like there is months, when days is 28 29 30 31, for ex if month have 30 days, but if date with 31 specified, then that date don't exist, but how to check any date i want?

Re: is date exist. - PeanutButter - 14.01.2017

I haven't tried it out, but you can use something like this function

PHP код:



stock checkdate(d,m,y)

{

   new daysinmonth[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

   new valid = 0;


   // leap year checking, if ok add 29 days to february

   if(y % 400 == 0 || (y % 100 != 0 && y % 4 == 0))

    daysinmonth[1]=29;


   // days in month checking

   if(m < 13)

   {

      if(d <= daysinmonth[m-1])

      {

          valid=1;

      }

   }

   return valid;

}

Re: is date exist. - SyS - 14.01.2017

Okay i re edited my code that i given before it will do the job as it is most common method / algorithm to validate a date in c programs.Ported version

PHP код:



bool:isValidDate(str[])

{

    new count;

    new daysinmonth[12]={31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

    new bool:legit;

    for(new i,j=strlen(str);i<j;i++)

        if(str[i]=='/')count++;



    if(count != 2) return false;


    new d,y,m;


    if(sscanf(str, "p</>iii", d, m, y))return false;


    if(d < 1 && d > 31) return false;


    if(m < 1 && m > 12) return false;


    

    if(y % 400 == 0 || (y % 100 != 0 && y % 4 == 0))

       daysinmonth[1]=29;


    if (m<13)

    {

      if( d <= daysinmonth[m-1] )

        legit=true;

    }


    if (!legit) return false;


    return true;


}

Re: is date exist. - Lordzy - 14.01.2017

Quote:

Originally Posted by Sreyas

Okay i re edited my code that i given before it will do the job as it is most common method / algorithm to validate a date in c programs.

PHP код:



bool:isValidDate(str[])

{

    new count;

    new daysinmonth[12]={31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

    new bool:legit;

    for(new i,j=strlen(str);i<j;i++)

        if(str[i]=='/')count++;



    if(count != 2) return false;


    new d,y,m;


    if(sscanf(str, "p</>iii", d, m, y))return false;


    if(d < 1 && d > 31) return false;


    if(m < 1 && m > 12) return false;


    

    if(y % 400 == 0 || (y % 100 != 0 && y % 4 == 0))

    daysinmonth[1]=29;


    if (m<13)

    {

      if( d <= daysinmonth[m-1] )

        legit=true;

    }


    if (!legit) return false;


    return true;


}

Not every date separators are "/" sign and also not every countries use (DD/MM/YYYY) format. Maybe you could an extra argument which helps to knows the date separator and format, thereby improving the function.

Re: is date exist. - SyS - 14.01.2017

Quote:

Originally Posted by Lordzy

Okay i write one but didn't test and seems to work

PHP код:



enum

{

DDMMYY,

DDYYMM,

MMDDYY,

MMYYDD,

YYDDMM,

YYMMDD

}


bool:isValidDate(str[],form=DDMMYY,seperator='/')

{

    new count;

    new daysinmonth[12]={31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

    new bool:legit;

    for(new i,j=strlen(str);i<j;i++)

        if(str[i]==seperator)count++;



    if(count != 2) return false;


    new d,y,m,string[9];

    format(string,sizeof(string),"p<%c>iii",seperator);


    if(form == DDMMYY)

        if(sscanf(str, string,d, m, y)) return false;


    else if(form == DDYYMM)

        if(sscanf(str, string,d, y, m)) return false;


    else if(form == MMDDYY)

        if(sscanf(str, string,m, d, y)) return false;

    

    else if(form == MMYYDD)

        if(sscanf(str, string,m, y, d)) return false;

    

    else if(form == YYDDMM)

        if(sscanf(str, string,y, d, m)) return false;

    

    else if(form == YYMMDD)

        if(sscanf(str, string,y, m, d)) return false;


    if(d < 1 && d > 31) return false;


    if(m < 1 && m > 12) return false;


    

    if(y % 400 == 0 || (y % 100 != 0 && y % 4 == 0))

                daysinmonth[1]=29;


    if (m<13)

    {

      if( d <= daysinmonth[m-1] )

                legit=true;

    }


    if (!legit) return false;


    return true;


}

Seems like it can optimise more what you think?

Re: is date exist. - MerryDeer - 14.01.2017

I too can use 01 02 03 04 05 06 07 08 09 in numbers, i mean sscanf understand it like 1 2 3 4 5 6 7 8 9 ?

Re: is date exist. - SyS - 14.01.2017

Quote:

Originally Posted by MerryDeer

I too can use 01 02 03 04 05 06 07 08 09 in numbers, i mean sscanf understand it like 1 2 3 4 5 6 7 8 9 ?

yes you can and also is that code working? I can't test it right now.

Re: is date exist. - MerryDeer - 14.01.2017

How to test to say it's working?

Re: is date exist. - SyS - 14.01.2017

Quote:

Originally Posted by MerryDeer

How to test to say it's working?

just add this function to your script and call it in main()
like this

PHP код:



main()

{

if(isValidDate("12/12/12",DDMMYY,'/') ) printf("Valid date"); //actually what now i passed is not required as it is default values check with others options too.

else printf("Not valid");

}

it should print "Valid date" in console.

Re: is date exist. - Vince - 14.01.2017

Quote:

Originally Posted by Lordzy

Doesn't really matter because you should set a standard for input. If I input 12/01/2017 the system can't know if I mean 12 January or 1 December. The internationally unambiguous ISO 8601 date format (YYYY-MM-DD) is probably the best.