MySQL problem -
Ripster - 02.01.2017
I have two strings. I'm formating:
Код:
new bankszamla[11], bankjelszo[5];
format(bankszamla, 11, "%d%d%d-%d%d%d-%d%d%d",random(9),random(9),random(9),random(9),random(9),random(9),random(9),random(9),random(9));
format(bankjelszo, 5, "%d%d%d%d%d",random(9),random(9),random(9),random(9),random(9));
For some reason they're not saved to the database, only the player's ID.
What's the problem?
Код:
mysql_format(mysql, query, sizeof(query), "INSERT INTO `accounts` (`Name`, `Password`, `IP`, `Admin`, `Level`, `Money`, `PosX`, `PosY`, `PosZ`, `PosA`, `Eletkor`, `Nem`, `Skin`, `Szarmazas`, `Health`, `Armor`, `BankEgyenleg`, `BankSzamla`, `BankJelszo`) VALUES ('%e', '%e', '%e', 0, 0, 0, %f, %f, %f, %f, %d, %d, %d, %d, 100.0, 0.0, 0, '%e', '%e')",
playername, Player[playerid][Password], playerip, SPAWN_X, SPAWN_Y, SPAWN_Z, SPAWN_A, Player[playerid][Adat][0], Player[playerid][Adat][1], Player[playerid][Adat][2], Player[playerid][Adat][3], bankszamla, bankjelszo);
mysql_tquery(mysql, query, "OnAccountRegister", "i", playerid);
Re: MySQL problem -
Vince - 02.01.2017
Strings need a null terminator else you will run into all sorts of problems. Means the sizes of your strings need to be at least 12 and 6 chars long, respectively. Also use sizeof instead of inserting the size literally. Sizeof is an operator, not a function, and has no impact on performance. Furthermore, instead of calling random(9) over and over again you can just do this:
PHP код:
format(bankszamla, sizeof(bankszamla), "%03d-%03d-%03d", random(1000), random(1000), random(1000));
PHP код:
format(bankjelszo, sizeof(bankjelszo), "%05d", random(100000));
Re: MySQL problem -
Ripster - 02.01.2017
thx, it works!